Java从整数获取月份字符串
问题内容:
有没有更好的方法来压缩此方法,即通过避免切换情况来降低圈复杂度?
String monthString;
switch (month) {
case 1: monthString = "January"; break;
case 2: monthString = "February"; break;
case 3: monthString = "March"; break;
case 4: monthString = "April"; break;
case 5: monthString = "May"; break;
case 6: monthString = "June"; break;
case 7: monthString = "July"; break;
case 8: monthString = "August"; break;
case 9: monthString = "September"; break;
case 10: monthString = "October"; break;
case 11: monthString = "November"; break;
case 12: monthString = "December"; break;
default: monthString = "Invalid month"; break;
}
System.out.println(monthString);
问题答案:
尝试:
import java.text.DateFormatSymbols;
monthString = new DateFormatSymbols().getMonths()[month-1];
另外,您可以使用SimpleDateFormat:
import java.text.SimpleDateFormat;
System.out.println(new SimpleDateFormat("MMMM").format(date));
(Date
要使用第二个选项,您必须在对象中添加日期和月份)。