Spring Mvc java.io.FileNotFoundException-ApplicationContext.xml
问题内容:
applicationContext.xml在WEB-INF文件夹中,为什么出现此错误:
org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [applicationContext.xml]; nested exception is java.io.FileNotFoundException: class path resource [applicationContext.xml] cannot be opened because it does not exist
Web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="crimeTrack" version="3.0">
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>log4jConfigLocation</param-name>
<param-value>/WEB-INF/classes/log4j.properties</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>crimetrack</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>crimetrack</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>
index.jsp
</welcome-file>
</welcome-file-list>
<jsp-config>
<taglib>
<taglib-uri>/spring</taglib-uri>
<taglib-location>/WEB-INF/tld/spring-form.tld</taglib-location>
</taglib>
</jsp-config>
</web-app>
问题答案:
我必须坚持使用 WEB-INF* 文件中的 / resources 目录,否则您可以随意命名。在 类路径 着眼于 WEB-
INF
目录但它会扫描该目录中的文件夹。我将 applicationContext.xml 和 servlet.xml 文件移动到
WEB-INF / resources 目录中,因此可以将其从 WEB-INF 的根目录中删除,并且无需维护
applicationContext.xml的 两个副本或 servlet.xml 文件。
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