分配之前可能会引用局部变量-Python


问题内容

我一直在尝试制作一个加密和解密系统,但遇到一个小错误。这是我的代码:

    import sys
    import pyperclip


    def copy(data):
        question = input("Copy to clipboard? ")

        if question.lower() == 'yes' or question.lower() == 'y':
            pyperclip.copy(data)
            print("Encrypted message copied to clipboard.")
            rerun()

        elif question.lower() == 'no' or question.lower() == 'n':
            rerun()

        else:
            print("You did not enter a valid input.")
            copy(data)


    def rerun():
        ask = input("\nWould you like to run this program again? ")

        if ask.lower() == "yes" or ask.lower() == "y":
            print(" ")
            run()

        elif ask.lower() == 'no' or ask.lower() == 'n':
            sys.exit("\nThank you!")

        else:
            print("You did not enter a valid input.")
            rerun()


    def encrypt(key, msg):
        encrypted_message = []
        for i, c in enumerate(msg):
            key_c = ord(key[i % len(key)])
            msg_c = ord(c)
            encrypted_message.append(chr((msg_c + key_c) % 127))
        return ''.join(encrypted_message)


    def decrypt(key, encrypted):
        msg = []
        for i, c in enumerate(encrypted):
            key_c = ord(key[i % len(key)])
            enc_c = ord(c)
            msg.append(chr((enc_c - key_c) % 127))
        return ''.join(msg)


    def run():
        function_type = input("Would you like to encrypt or decrypt a message? ")

        if function_type.lower() == "encrypt" or function_type.lower() == "e":
            key = input("\nKey: ")
            msg = input("Message: ")
            data = encrypt(key, msg)
            enc_message = "\nYour encrypted message is: " + data
            print(enc_message)
            copy(data)

        elif function_type.lower() == "decrypt" or function_type.lower() == "d":
            key = input("\nKey: ")

            question = input("Paste encrypted message from clipboard? ")

            if question.lower() == 'yes' or question.lower() == 'y':
                encrypted = pyperclip.paste()
                print("Message: " + encrypted)

            elif question.lower() == 'no' or question.lower() == 'n':
                encrypted = input("Message: ")

            else:
                print("You did not enter a valid input.")
                run()

            decrypted = decrypt(key, encrypted)
            decrypted_message = "\nYour decrypted message is: " + decrypted
            print(decrypted_message)
            copy(decrypted)

        else:
            print("\nYou did not enter a valid input.\n")
            run()

    run()

它说 本地变量“加密”可能在赋值 和突出显示 之前被引用

    decrypted = decrypt(key, encrypted)

在run()函数下。

是因为我在其他函数中使用了变量“ encrypted”吗?如果是这样,我将如何解决此问题并仍然保持程序的功能?

我是python的新手,所以如果您能解释一下答案,我将不胜感激。


问题答案:

分配之前可能会引用局部变量“ encrypted”

是短绒产生的警告。

这是因为linter看到encrypted两个if条件内的赋值

 if question.lower() == 'yes' or question.lower() == 'y':

elif question.lower() == 'no' or question.lower() == 'n':

但是,如果条件是相互补充的,则短毛猫无法知道这两个条件。因此,考虑到所有条件都不为真的情况,变量encrypted将最终未初始化。

要消除此警告,您可以在任何if带有Nonevalue的条件之前简单地初始化变量