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0-23小时军事时钟到标准时间（hh：mm）

问题内容：

我将如何进行此过程？假设有人输入“ 3：5”，我应该能够得到输出“ 3:05 AM”。或者，如果有人输入“ 00:00”，我应该得到“ 12:00
AM”。如果将时间格式简单地输入为“ hhmm”，我就会意识到有很多解决方法，但是输入的范围可以是“ h：m”，“ hh：m”，“ hh：m”和“
hh：毫米”。所以这是非常情况。

def timeConvert():
    miliTime = int(input("Enter a time in hh:mm (military) format: "))
    miliTime.split(":")
    if len(miliTime) == 3:
        hours = miliTime[0]
        minutes = miliTime[2]
        if hours < 0:
            print("Hours can't be less than 0.")
    elif len(miliTime) == 4:
        if miliTime[0:2] >= 10:
            hours = militime[0:2]
            minutes = militime[3]
            if minutes < 0:
                print("Minutes can't be less than 0.")
            if minutes < 10:
                minutes = 0 + minutes
        else:
            hours = miliTime[0]
            minutes = militime[2:]
            if minutes >= 60:
                print("Too big of a number for minutes.")
    else:
        hours = miliTime[0:2]
        minutes = miliTime[3:]
    setting = AM
    if hours > 12:
        setting = PM
        hours -= 12
    print(hours + ":" + minutes + setting)

timeConvert()

问题答案：

用分割输入:，最后使用格式化的输出：

def timeConvert():
    miliTime = input("Enter a time in hh:mm (military) format: ")
    hours, minutes = miliTime.split(":")
    hours, minutes = int(hours), int(minutes)
    setting = "AM"
    if hours > 12:
        setting = "PM"
        hours -= 12
    print(("%02d:%02d" + setting) % (hours, minutes))