检测与圆角的矩形碰撞

问题内容：

我有一个带有中心点的圆（Center_X，Center_Y），并且正在检测矩形是否落入其半径（半径）。我将如何执行此任务？我尝试使用

if (X - Center_X)^2 + (Y - Center_Y)^2 < Radius^2:
        print(1)

然后，我尝试画一个圆以适合该区域：

Circle = pygame.draw.circle(Window, Blue, (Center_X, Center_Y), Radius, 0)

但它似乎没有排队。我做错什么了吗？

问题答案：

这是我在评论中所描述的内容，并进行了更改，以正确处理迈克尔·安德森在评论中指出的较大矩形内的圆形情况：

import math

def collision(rleft, rtop, width, height,   # rectangle definition
              center_x, center_y, radius):  # circle definition
    """ Detect collision between a rectangle and circle. """

    # complete boundbox of the rectangle
    rright, rbottom = rleft + width/2, rtop + height/2

    # bounding box of the circle
    cleft, ctop     = center_x-radius, center_y-radius
    cright, cbottom = center_x+radius, center_y+radius

    # trivial reject if bounding boxes do not intersect
    if rright < cleft or rleft > cright or rbottom < ctop or rtop > cbottom:
        return False  # no collision possible

    # check whether any point of rectangle is inside circle's radius
    for x in (rleft, rleft+width):
        for y in (rtop, rtop+height):
            # compare distance between circle's center point and each point of
            # the rectangle with the circle's radius
            if math.hypot(x-center_x, y-center_y) <= radius:
                return True  # collision detected

    # check if center of circle is inside rectangle
    if rleft <= center_x <= rright and rtop <= center_y <= rbottom:
        return True  # overlaid

    return False  # no collision detected

检测与圆角的矩形碰撞

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