在scrapy框架python的start_urls列表中为url构造正则表达式
问题内容:
我对Scrapy非常陌生,而且之前我没有使用过正则表达式
以下是我的spider.py
代码
class ExampleSpider(BaseSpider):
name = "test_code
allowed_domains = ["www.example.com"]
start_urls = [
"http://www.example.com/bookstore/new/1?filter=bookstore",
"http://www.example.com/bookstore/new/2?filter=bookstore",
"http://www.example.com/bookstore/new/3?filter=bookstore",
]
def parse(self, response):
hxs = HtmlXPathSelector(response)
现在,如果我们查看start_urls
所有三个url相同,除了它们的整数值不同,2?, 3?
依此类推,我的意思是根据网站上存在的url不受限制,我现在我们可以使用crawlspider并可以为该URL构造正则表达式,如下所示,
from scrapy.contrib.spiders import CrawlSpider, Rule
from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor
import re
class ExampleSpider(CrawlSpider):
name = 'example.com'
allowed_domains = ['example.com']
start_urls = [
"http://www.example.com/bookstore/new/1?filter=bookstore",
"http://www.example.com/bookstore/new/2?filter=bookstore",
"http://www.example.com/bookstore/new/3?filter=bookstore",
]
rules = (
Rule(SgmlLinkExtractor(allow=(........),))),
)
def parse(self, response):
hxs = HtmlXPathSelector(response)
您能否指导我,如何为以上start_url
列表构建爬网蜘蛛规则。
问题答案:
如果我正确理解您的要求,则需要大量具有特定模式的起始URL。
如果是这样,则可以重写BaseSpider.start_requests方法:
class ExampleSpider(BaseSpider):
name = "test_code"
allowed_domains = ["www.example.com"]
def start_requests(self):
for i in xrange(1000):
yield self.make_requests_from_url("http://www.example.com/bookstore/new/%d?filter=bookstore" % i)
...