我的jsps在WEB-INF / jsp /下，以下是我的web.xml：

<!DOCTYPE web-app PUBLIC
 "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
 "http://java.sun.com/dtd/web-app_2_3.dtd" >

<web-app>
  <display-name>Checkout</display-name>

  <servlet>
    <servlet-name>myservlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>

  <servlet-mapping>
    <servlet-name>myservlet</servlet-name>
    <url-pattern>*.action</url-pattern>
  </servlet-mapping>


</web-app>

这是我尝试访问的product.jsp页面的映射：

@Controller
@RequestMapping("/product.action")
public class ProductController {

    /**
     * Show the product selection form
     * 
     * @return
     */
    @RequestMapping(method=RequestMethod.GET)
    public String get() {
        return "products.jsp";
    }

}

尝试通过以下链接访问页面时：

http://localhost:8080/myapp/product.action

我进入404浏览器，并且在控制台中收到以下警告：

Jun 28, 2012 10:55:23 AM org.springframework.web.servlet.DispatcherServlet noHandlerFound
WARNING: No mapping found for HTTP request with URI [/myapp/product.action] in DispatcherServlet with name 'myservlet'

我在配置中缺少什么吗？请指教，谢谢。

编辑 ：我试图添加viewResolver bean到applicationContext没有运气：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd">

    <context:component-scan base-package="com.myapp"/>



    <bean id="viewResolver"
      class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="prefix" value="/WEB-INF/jsp/"/>
    <property name="suffix" value=".jsp"/>
   </bean>


</beans>