热门文章
 当前位置：技术文章 > 编程面试题 >

生成器无法按特定标识符拆分字符串。Python 2

问题内容：

到目前为止，我已经找到一种产生名称，字符串和额外字符串的方法。它适用于第二个，但不适用于第一个吗？太奇怪了，因为格式真的很相似。是因为它是多行吗？我以为if line == '+': pass会绕过这个问题。

我在打印’\ n’中添加以显示差异

输入：

@first_name
AlongStringOfText
ThatHasNoSpaces
ButIsSeparatedByLineBreaks
+
{+iuhsfIUHSDFUi8849308989829
0990+-]@@@#*$()(@*$*)))***)@@**@#*u
sdfiuhnknwuiewi
+
@second_name
MoreTextThatCouldBeOnOneLine
+
+{~~~(@#UhuisdfiuhIUHDSFIUFHIl)}9823)88hafff
#empty line at end

当前脚本：

def organize(input_file):
    name = None
    body = ''
    extra = ''
    for line in input_file:
        line = line.strip()
        if line.startswith('@'):
            if name: 
                yield name, body, extra
                body = ''
                extra = ''
            name = line
        else:
            body = body + line
            if line == '+':
                pass
    print '\n'
    body,extra = body.split('+',1)

    yield name,body,extra

for line in organize(file_path):
    print line

输出：

('@first_name', 'AlongStringOfTextThatHasNoSpacesButIsSeparatedByLineBreaks+{+iuhsfIUHSDFUi88493089898290990+-]@@@#*$()(@*$*)))***)@@**@#*usdfiuhnknwuiewi+', '')


('@second_name', 'MoreTextThatCouldBeOnOneLine', '+{~~~(@#UhuisdfiuhIUHDSFIUFHIl)}9823)88hafff')

所需输出：

('@first_name','AlongStringOfTextThatHasNoSpacesButIsSeparatedByLineBreaks','{+iuhsfIUHSDFUi88493089898290990+-]@@@#*$()(@*$*)))***)@@**@#*usdfiuhnknwuiewi')
('@second_name','MoreTextThatCouldBeOnOneLine','+{~~~(@#UhuisdfiuhIUHDSFIUFHIl)}9823)88hafff')

问题答案：

实际的问题是，您不split屈服。所以像这样更改代码

    if line.startswith('@'):
        if name: 
            body, extra = body.split('+',1)
            yield name, body, extra
            body = ''
        name = line
    else:
        body = body + line
body, extra = body.split('+',1)
yield name, body, extra

另外，以下if条件在程序输出中不起作用

if line == '+':
    pass

因此，我在上面的代码中将其删除。