Spring MVC @RequestBody接收具有非原始属性的对象包装

问题内容：

我按如下方式创建JSON：

    var manager = {
        username: "admin",
        password: "admin"
    };
    var userToSubscribe = {
        username: "newuser",
        password: "newpassword",
        email: "user@1and1.es"
    };

    var openid = "myopenid";

    var subscription = {
            manager: manager,
            userToSubscribe : userToSubscribe,
            openid : openid
    };

    $.ajax({
        url: '/myapp/rest/subscribeUser.json',
        type: 'POST',
        dataType: 'json',
        contentType: 'application/json',
        mimeType: 'application/json',
        data: JSON.stringify({subscription : subscription})   
    });

这是发送的JSON：

{"subscription":{"manager":{"username":"admin","password":"admin"},"userToSubscribe":{"username":"newuser","password":"newpassword","email":"user@1and1.es"},"openid":"myopenid"}}

我想将此JSON映射到Wrapper类。这是包装器：

private class Subscription{
    private User manager;
    private User userToSubscribe;
    private String openid;
    public User getManager() {
        return manager;
    }
    public void setManager(User manager) {
        this.manager = manager;
    }
    public User getUserToSubscribe() {
        return userToSubscribe;
    }
    public void setUserToSubscribe(User userToSubscribe) {
        this.userToSubscribe = userToSubscribe;
    }
    public String getOpenid() {
        return openid;
    }
    public void setOpenid(String openid) {
        this.openid = openid;
    }
}

pom.xml中的杰克逊依赖关系（我正在使用spring 3.1.0.RELEASE）：

    <dependency>
        <groupId>org.codehaus.jackson</groupId>
        <artifactId>jackson-mapper-asl</artifactId>
        <version>1.9.10</version>
    </dependency>

rest-servlet.xml中的映射

<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
   <property name="messageConverters">
       <list>
           <ref bean="jsonConverter" />
       </list>
   </property>
</bean>

<bean id="jsonConverter" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter">
   <property name="supportedMediaTypes" value="application/json" />
</bean>

和控制器方法的标头：

public @ResponseBody SimpleMessage subscribeUser(@RequestBody Subscription subscription)

由于POST，我收到400错误请求请求错误。是否可以执行此操作，或者我是否需要使用@RequestBodyString进行操作或@RequestBody Map<String,Object>自己解码JSON？

谢谢！

问题答案：

我要回答我自己的问题。首先要特别感谢Sotirios Delimanolis，因为他给了我钥匙以调查发生了什么。

如您所知，我从视图创建以下json：

{"manager":{"username":"admin","password":"admin"},"userToSubscribe":{"username":"newuser","password":"newpassword","email":"user@1and1.es"},"openid":"https://myopenid..."}

我做了一点修改，因为我意识到创建对象订阅和var订阅不是必需的。如果您像这样构建JSON，它将可以完美地工作：

var manager = {
    username: "admin",
    password: "admin"
};
var userToSubscribe = {
    username: "newuser",
    password: "newpassword",
    email: "user@1and1.es"
};

var openid = "https://myopenid...";

$.ajax({
    url: '/dp/rest/isUserSuscribed.json',
    type: 'POST',
    dataType: 'json',
    contentType: 'application/json',
    mimeType: 'application/json',
    data: JSON.stringify({manager : manager, userToSubscribe : userToSubscribe, openid : openid})   
});

控制器收到以下json：

@RequestMapping(method=RequestMethod.POST, value="/isUserSuscribed.json")
public @ResponseBody ResponseMessageElement<Boolean> isUserSuscribed(@RequestBody SubscriptionWrapper subscription){

还有SubscriptionWrapper …

private static class SubscriptionWrapper {
    BasicUser manager;
    BasicUser userToSubscribe;
    String openid;

    public BasicUser getManager() {
        return manager;
    }
    public void setManager(BasicUser manager) {
        this.manager = manager;
    }
    public BasicUser getUserToSubscribe() {
        return userToSubscribe;
    }
    public void setUserToSubscribe(BasicUser userToSubscribe) {
        this.userToSubscribe = userToSubscribe;
    }
    public String getOpenid() {
        return openid;
    }
    public void setOpenid(String openid) {
        this.openid = openid;
    }
}

那是什么问题我收到了一个不正确的Request
400错误…我按照Sotirios的建议调试了MappingJackson2HttpMessageConverter，但发生了异常（没有合适的构造函数）。无论此类不是静态的，Jackson
Mapping都无法构建内部类。将SubscriptionWrapper设置为静态是解决我的问题的方法。

您还可以检查以下答案： http://stackoverflow.com/questions/8526333/jackson-error-no- suitable-constructor

http://stackoverflow.com/questions/12139380/how-to-convert-json-into-pojo-in- java-using-jackson

如果您有反序列化的问题，请检查以下内容： http://stackoverflow.com/questions/17400850/is-jackson- really-unable-to-deserialize-json-into-a-generic-type

感谢所有的答复。

Spring MVC @RequestBody接收具有非原始属性的对象包装

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