提问者:小点点

JQUERY多个IF条件


我试图对这个validateForm函数应用多个条件,使某些表单字段成为非强制性的。 if条件if((y[i].value==“”&&y[i].name!=“phone”))

可以使单个字段成为非强制字段,但当我应用多个条件使多个字段成为非强制字段时,例如;


if ((y[i].value == "" && y[i].name!="phone") || (y[i].value == "" && y[i].name!="yyyy")){

// add an "invalid" class to the field:
      y[i].className += " invalid";
      // and set the current valid status to false
      valid = false;

}


好像不起作用。 所有字段再次变为必填字段。 请问我做错了什么?

完整的守则抄录自W3学校,详情如下:


var currentTab = 0; // Current tab is set to be the first tab (0)
showTab(currentTab); // Display the current tab

function showTab(n) {
  // This function will display the specified tab of the form...
  var x = document.getElementsByClassName("tab");
  x[n].style.display = "block";
  //... and fix the Previous/Next buttons:
  if (n == 0) {
    document.getElementById("prevBtn").style.display = "none";
  } else {
    document.getElementById("prevBtn").style.display = "inline";
  }
  if (n == (x.length - 1)) {
    document.getElementById("nextBtn").innerHTML = "Submit";
  } else {
    document.getElementById("nextBtn").innerHTML = "Next";
  }
  //... and run a function that will display the correct step indicator:
  fixStepIndicator(n)
}

function nextPrev(n) {
  // This function will figure out which tab to display
  var x = document.getElementsByClassName("tab");
  // Exit the function if any field in the current tab is invalid:
  if (n == 1 && !validateForm()) return false;
  // Hide the current tab:
  x[currentTab].style.display = "none";
  // Increase or decrease the current tab by 1:
  currentTab = currentTab + n;
  // if you have reached the end of the form...
  if (currentTab >= x.length) {
    // ... the form gets submitted:
    document.getElementById("regForm").submit();
    return false;
  }
  // Otherwise, display the correct tab:
  showTab(currentTab);
}

function validateForm() {
  // This function deals with validation of the form fields
  var x, y, i, valid = true;
  x = document.getElementsByClassName("tab");
  y = x[currentTab].getElementsByTagName("input");
  // A loop that checks every input field in the current tab:
  for (i = 0; i < y.length; i++) {
    // If a field is empty...
    if (y[i].value == "" && y[i].name!="phone") 
    {
      // add an "invalid" class to the field:
      y[i].className += " invalid";
      // and set the current valid status to false
      valid = false;

    }

  }
  // If the valid status is true, mark the step as finished and valid:
  if (valid) {
    document.getElementsByClassName("step")[currentTab].className += " finish";
  }
  return valid; // return the valid status
}




function fixStepIndicator(n) {
  // This function removes the "active" class of all steps...
  var i, x = document.getElementsByClassName("step");
  for (i = 0; i < x.length; i++) {
    x[i].className = x[i].className.replace(" active", "");
  }
  //... and adds the "active" class on the current step:
  x[n].className += " active";
}

提前谢谢你。


共1个答案

匿名用户

您可以尝试:

null

const criteriaOptions = ["phone", "yyyy"]

if (y[i].value == "" && !criteriaOptions.includes(y[i].name)) {

// add an "invalid" class to the field:
      y[i].className += " invalid";
      // and set the current valid status to false
      valid = false;

}