提问者:小点点

无法使用SpringBoot中的控制器通知返回rest api响应


无法使用控制器建议返回RestApiResponse。

解决方案已实施

**我的方法**

1)我创建了一个抛出异常的Controller。

2)全局异常处理程序将使用@控制程序捕获异常。

3)特定方法将返回响应作为APIResponse。

{
"timestamp": 1519377824339,
"status": 404,
"error": "Not Found",
"exception": "java.lang.Exception",
"message": "No message available",
"path": "/test"
}

System. out.println(“此处收到异常请求”);

{
"success": false,
"message": "null Your Exception ",
"object": null
}  
@RequestMapping("/test")
@RestController
public class TestController  {

@Autowired
private UserService userService;

@PostMapping
ApiResponse<User> post(@RequestBody User user) throws Exception {
    if(true)
        throw new Exception();
    return ApiResponse.success().object(userService.post(user));
}
}

@ControllerAdvice
public class GlobalExceptionHandlerController {

@ExceptionHandler(value = Exception.class)
public ApiResponse<Void> handleDefaultException(Exception exception) {
    System.out.println(" Request Received Here for Exception ");
    return ApiResponse.failure().message(exception.getMessage() + "Please check your Response").build();
}
}
public class ApiResponse<T> {
private boolean success;
private String message;
private T object;

public static class ResponseBuilder {
    private boolean success;
    private String message;

    private ResponseBuilder(boolean success) {
        this.success = success;
        this.message = "";
    }

    public ResponseBuilder message(String message) {
        this.message = message;
        return this;
    }

    public <C> ApiResponse<C> object(C object) {
        return new ApiResponse<C>(success, message, object);
    }

    public <C> ApiResponse<C> build() {
        return new ApiResponse<>(success, message, null);
    }
}

public static ResponseBuilder success() {
    return new ResponseBuilder(true);
}

public static ResponseBuilder failure() {
    return new ResponseBuilder(false);
}

private ApiResponse(boolean success, String message, T object) {
    this.success = success;
    this.message = message;
    this.object = object;
}

public boolean isSuccess() {
    return success;
}

public void setSuccess(boolean success) {
    this.success = success;
}

public String getMessage() {
    return message;
}

public void setMessage(String message) {
    this.message = message;
}

public T getObject() {
    return object;
}

public void setObject(T object) {
    this.object = object;
}
}

localhost:6005/test

{
 "name":"jalaj"
}
 <parent>
    <groupId>org.springframework.boot</groupId>
    <artifactId>spring-boot-starter-parent</artifactId>
    <version>1.5.10.RELEASE</version>
    <relativePath/> <!-- lookup parent from repository -->
 </parent>

<dependencies>
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-data-jpa</artifactId>
    </dependency>
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-data-mongodb</artifactId>
    </dependency>
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-web</artifactId>
    </dependency>

    <dependency>
        <groupId>mysql</groupId>
        <artifactId>mysql-connector-java</artifactId>
        <scope>runtime</scope>
    </dependency>
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-test</artifactId>
        <scope>test</scope>
    </dependency>
</dependencies>

我只能从输出中判断我的控制器没有执行。

您可以从我的bitbucket配置文件中下载代码以查看我的代码。

https://bitbucket.org/JalajChawla/

如果我错过了什么,有人能指导我吗?


共1个答案

匿名用户

只需从GlobalExceptionHandlerControllerTestController扩展

@RequestMapping("/test")
@RestController
public class TestController extends GlobalExceptionHandlerController