提问者:小点点

将上传的图像保存在不同大小的服务器文件夹中


这里是我的代码,在那里我已经尝试了几个小时,将上传的图像保存在不同大小的服务器文件夹中。但是,图像没有被保存,并且无法得到它出错的地方。以前,我使用二进制代码编写,如下面的第二个代码部分所示,通过从移动端以某种方式带来二进制数据(图片是从相机中获取的,并从移动端即时发送)。但随着数据的增加。我决定使用甚至上传图像文件与多部分类型的文件上传从我的移动端。

<?php

$imagefile = $_FILES["uploadphoto1"]["name"];
$errors=0;
$uploadPath  = __DIR__."/contents/uploads";
define ("MAX_SIZE","4000");

$imagename = "testingimage";

if($imagefile)
{
    $filename = stripslashes($_FILES['uploadphoto1']['name']);
    $extension = getExtension($filename);
    $extension = strtolower($extension);

if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif"))
    {
        echo ' Unknown Image extension ';
        $errors=1;
    }
    else
    {

        $file1 = $_FILES['uploadphoto1']['tmp_name'];

        thumbnail_image($file1, "640", "480",$uploadPath.$imagename);
        thumbnail_image($file1, "480", "340",$uploadPath.$imagename."_preview");

    }
}else{
    echo "No file is inserted>>>>>>>>>";
}

function thumbnail_image($original_file_path, $new_width, $new_height, $save_path="")
{
    $imgInfo = getimagesize($original_file_path);
    $imgExtension = "";

    switch ($imgInfo[2])
    {
        case 1:
            $imgExtension = '.gif';
            break;

        case 2:
            $imgExtension = '.jpg';
            break;

        case 3:
            $imgExtension = '.png';
            break;
    }

    if ($save_path=="") $save_path = "thumbnail".$imgExtension ;

    // Get new dimensions
    list($width, $height) = getimagesize($original_file_path);

    // Resample
    $imageResample = imagecreatetruecolor($new_width, $new_height);

    if ( $imgExtension == ".jpg" )
    {
        $image = imagecreatefromjpeg($original_file_path);
    }
    else if ( $imgExtension == ".gif" )
    {
        $image = imagecreatefromgif($original_file_path);
    }
    else if ( $imgExtension == ".png" )
    {
        $image = imagecreatefrompng($original_file_path);
    }

    imagecopyresampled($imageResample, $image, 0, 0, 0, 0, $new_width, $new_height, $width, $height);

    if ( $imgExtension == ".jpg" )
        imagejpeg($imageResample, $save_path.$imgExtension);
    else if ( $imgExtension == ".gif" )
        imagegif($imageResample, $save_path.$imgExtension);
    else if ( $imgExtension == ".png" )
        imagepng($imageResample, $save_path.$imgExtension);

}

function getExtension($str) {

    $i = strrpos($str,".");
    if (!$i) { return ""; }

    $l = strlen($str) - $i;
    $ext = substr($str,$i+1,$l);
    return $ext;
}

if(isset($_POST['Submit']) && !$errors)
{
    echo "Image Uploaded Successfully!";

}else{
    echo "Image uploading failed>>>>>>>";
     }

?>

但下面的工作与我以前获取二进制数据时的相同函数,但这段代码根本不包含在我现在的代码中:

$file1   = tempnam($uploadPath, 'image1');
$fp1     = fopen($file1, 'wb');
fwrite($fp1, $binary1);// Here I have binary data of image. 
fclose($fp1);

thumbnail_image($file1, "640", "480",$uploadPath.$imagelastid.".jpg");

thumbnail_image($file1, "480", "340",$uploadPath.$imagelastid."_preview.jpg");

如果有人能帮我解决这件事,让我步入正轨,我会非常感激的。

我得到这个错误:

getimagesize(): Read error! in C:\xampp\htdocs\MOBILE_PHP\imagephptest.php on line 48

其中48行是-->$IMGINFO=getimagesize($Original_FILE_PATH);

有时我会在同一行上得到这个错误。

getImageSize():C:\xampp\htdocs\mobile_php\imagephptest.php第44行中的文件名不能为空


共2个答案

匿名用户

list($width, $height, $type, $attr) = getimagesize($original_file_path);
$widthheight="$width X $height";

这将首先给出图像的宽度和高度。

匿名用户

我怀疑问题出在这2行:

$file1 = $_FILES['uploadphoto1']['tmp_name'];
$file1   = tempnam($uploadPath, 'image1');

获取上传图像的临时名称并将其保存在$FILE1中,然后重写该值并创建临时文件。之后,您将它传递给您的函数,当您尝试

getimagesize($original_file_path);

它会失败,因为$Original_FILE_PATH甚至不是映像。