当我将两个Sql查询放在一个页面中时,我在显示表时遇到了问题。 我没有这个问题,当我只放1个查询。
我想从student table
中显示学生的列表,讲师可以添加需要他们照顾的学生,这将具有添加功能。 我已经做了编码,但我遇到了问题。
这是我的密码
<table id=" table" class="table table-bordered">
<thead>
<tr>
<th>Student ID</th>
<th>Name</th>
<th>Email</th>
<th>Contact Number</th>
<th>Programme Type</th>
<th>Status</th>
<th>Action</th>
</tr>
</thead>
<tbody>
<?php
$query = mysqli_query($conn, "SELECT * FROM `student`") or die(mysqli_error());
while($fetch = mysqli_fetch_array($query)){
?>
<tr class="del_student<?php echo $fetch['student_id']?>">
<td><?php echo $fetch['student_id']?></td>
<td><?php echo $fetch['student_name']?></td>
<td><?php echo $fetch['student_email']?></td>
<td><?php echo $fetch['contact_number']?></td>
<td><?php echo $fetch['programme_type']?></td>
<td><?php echo $fetch['status_type']?></td>
<td><center><button class="btn btn-warning" data-toggle="modal" data-target="#edit_modal<?php echo $fetch['student_id']?>"><span class="glyphicon glyphicon-edit"></span> Edit</button> </center>
</td>
</tr>
<div class="modal fade" id="edit_modal<?php echo $fetch['student_id']?>" aria-hidden="true">
<div class="modal-dialog modal-dialog-centered">
<div class="modal-content">
<form method="POST" action="update_student.php">
<div class="modal-header">
<h4 class="modal-title">Add Supervisee</h4>
</div>
<div class="modal-body">
<div class="col-md-3"></div>
<div class="col-md-6">
<div class="form-group">
<label>Student ID</label>
<input type="hidden" name="id" value="<?php echo $fetch['id']?>" class="form-control"/>
<input type="number" name="student_id" value="<?php echo $fetch['student_id']?>" class="form-control" required="required"/>
</div>
<div class="form-group">
<label>Student Name</label>
<input type="text" name="student_name" value="<?php echo $fetch['student_name']?>" class="form-control" required="required"/>
</div>
<div class="form-group">
<label>Student Email</label>
<input type="email" name="student_email" value="<?php echo $fetch['student_email']?>" class="form-control" required="required"/>
</div>
<div class="form-group">
<label>Contact Number </label>
<input type="text" name="contact_number" value="<?php echo $fetch['contact_number']?>" class="form-control" required="required"/>
</div>
<div class="form-group">
<label>Programme Type</label>
<input type="text" name="programme_type" value="<?php echo $fetch['programme_type']?>" class="form-control" required="required"/>
</div>
<div class="form-group">
<label>Status</label>
<input type="text" name="status_type" value="<?php echo $fetch['status_type']?>" class="form-control" required="required"/>
</div>
<label>Supervisor Information</label>
<div class="form-group">
<?php
$query = mysqli_query($conn, "SELECT * FROM `supervisor` WHERE `user_id` = '$_SESSION[user]'") or die(mysqli_error());
$fetch = mysqli_fetch_array($query);
$user_id = $fetch['work_id'];
?>
<label>Supervisor ID</label>
<input type="text" name="supervisor_id" value="<?php echo $fetch['work_id']?>" class="form-control" required="required"/>
</div>
<div class="form-group">
<label>Supervisor Name</label>
<input type="text" name="supervisor_name" value="<?php echo $fetch['name']?>" class="form-control" required="required"/>
</div>
<div class="form-group">
<label>Supervisor Role </label>
<select name="supervisor_role" class="form-control" required="required">
<option value="Chose supervisor role"></option>
<option value="Supervisor">Supervisor</option>
<option value="Co - Supervisor">Co-Supervisor</option>
</select>
</div>
</div>
</div>
<div style="clear:both;"></div>
<div class="modal-footer">
<button type="button" class="btn btn-danger" data-dismiss="modal"><span class="glyphicon glyphicon-remove"></span> Close</button>
<button name="update" class="btn btn-warning" ><span class="glyphicon glyphicon-save"></span> Update</button>
</div>
</form>
</div>
</div>
<?php
}
?>
</tbody>
</table>
</div>
</div>
我注意到,当我将此查询放入表中时,表中没有显示学生的完整列表
<?php
$query = mysqli_query($conn, "SELECT * FROM `supervisor` WHERE `user_id` = '$_SESSION[user]'") or die(mysqli_error());
$fetch = mysqli_fetch_array($query);
$user_id = $fetch['work_id'];
?>
我想要实现的是我想要在数据库中显示所有已经注册的学生,并且讲师可以添加学生,学生信息连同讲师的id和姓名将被保存到数据库中。 如何修复这个问题?
您正在使用$fetch
从这两个查询中获取结果。
下面是代码中发生的情况。
$fetch
从学生表中获取结果。$fetch
值将更改。 因此,学生表只显示1行。将第二个查询中的$fetch
更改为其他内容,如$fetch2